.2x^2-48x=300

Solution for .2x^2-48x=300 equation:

.2x^2-48x=300

We move all terms to the left:

.2x^2-48x-(300)=0

a = .2; b = -48; c = -300;
Δ = b2-4ac
Δ = -482-4·.2·(-300)
Δ = 2544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2544}=\sqrt{16*159}=\sqrt{16}*\sqrt{159}=4\sqrt{159}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-4\sqrt{159}}{2*.2}=\frac{48-4\sqrt{159}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+4\sqrt{159}}{2*.2}=\frac{48+4\sqrt{159}}{0.4}
$